16x2-24x-141=0

Solution for 16x2-24x-141=0 equation:

16x^2-24x-141=0

a = 16; b = -24; c = -141;
Δ = b2-4ac
Δ = -242-4·16·(-141)
Δ = 9600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9600}=\sqrt{1600*6}=\sqrt{1600}*\sqrt{6}=40\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-40\sqrt{6}}{2*16}=\frac{24-40\sqrt{6}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+40\sqrt{6}}{2*16}=\frac{24+40\sqrt{6}}{32}
$