22/3d+1/2d=95

Solution for 22/3d+1/2d=95 equation:

22/3d+1/2d=95

We move all terms to the left:

22/3d+1/2d-(95)=0


Domain of the equation: 3d!=0

d!=0/3

d!=0

d∈R



Domain of the equation: 2d!=0

d!=0/2

d!=0

d∈R


We calculate fractions


44d/6d^2+3d/6d^2-95=0

We multiply all the terms by the denominator


44d+3d-95*6d^2=0

We add all the numbers together, and all the variables

47d-95*6d^2=0

Wy multiply elements

-570d^2+47d=0

a = -570; b = 47; c = 0;
Δ = b2-4ac
Δ = 472-4·(-570)·0
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2209}=47$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(47)-47}{2*-570}=\frac{-94}{-1140}
=47/570
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(47)+47}{2*-570}=\frac{0}{-1140}
=0
$