3(x-2)-5=1-2(x+1)

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Solution for 3(x-2)-5=1-2(x+1) equation: 



3(x-2)-5=1-2(x+1)

We move all terms to the left:

3(x-2)-5-(1-2(x+1))=0

We multiply parentheses

3x-(1-2(x+1))-6-5=0



We calculate terms in parentheses: -(1-2(x+1)), so:

1-2(x+1)

determiningTheFunctionDomain
-2(x+1)+1

We multiply parentheses

-2x-2+1

We add all the numbers together, and all the variables

-2x-1

Back to the equation:

-(-2x-1)



We add all the numbers together, and all the variables

3x-(-2x-1)-11=0

We get rid of parentheses

3x+2x+1-11=0

We add all the numbers together, and all the variables

5x-10=0

We move all terms containing x to the left, all other terms to the right

5x=10

x=10/5

x=2

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