22-5x=2(3+6x)

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Solution for 22-5x=2(3+6x) equation: 



22-5x=2(3+6x)

We move all terms to the left:

22-5x-(2(3+6x))=0

We add all the numbers together, and all the variables

-5x-(2(6x+3))+22=0



We calculate terms in parentheses: -(2(6x+3)), so:

2(6x+3)

We multiply parentheses

12x+6

Back to the equation:

-(12x+6)



We get rid of parentheses

-5x-12x-6+22=0

We add all the numbers together, and all the variables

-17x+16=0

We move all terms containing x to the left, all other terms to the right

-17x=-16

x=-16/-17

x=16/17

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