2(y-1)=4y-(y+2)

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Solution for 2(y-1)=4y-(y+2) equation: 



2(y-1)=4y-(y+2)

We move all terms to the left:

2(y-1)-(4y-(y+2))=0

We multiply parentheses

2y-(4y-(y+2))-2=0



We calculate terms in parentheses: -(4y-(y+2)), so:

4y-(y+2)

We get rid of parentheses

4y-y-2

We add all the numbers together, and all the variables

3y-2

Back to the equation:

-(3y-2)



We get rid of parentheses

2y-3y+2-2=0

We add all the numbers together, and all the variables

-y=0

y=0/-1

y=0

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