22-4x=-8(3x-2)+6

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Solution for 22-4x=-8(3x-2)+6 equation: 



22-4x=-8(3x-2)+6

We move all terms to the left:

22-4x-(-8(3x-2)+6)=0



We calculate terms in parentheses: -(-8(3x-2)+6), so:

-8(3x-2)+6

We multiply parentheses

-24x+16+6

We add all the numbers together, and all the variables

-24x+22

Back to the equation:

-(-24x+22)



We get rid of parentheses

-4x+24x-22+22=0

We add all the numbers together, and all the variables

20x=0

x=0/20

x=0

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