8(1-4n)-7n=5n-2(-4+3n)

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Solution for 8(1-4n)-7n=5n-2(-4+3n) equation: 



8(1-4n)-7n=5n-2(-4+3n)

We move all terms to the left:

8(1-4n)-7n-(5n-2(-4+3n))=0

We add all the numbers together, and all the variables

8(-4n+1)-7n-(5n-2(3n-4))=0

We add all the numbers together, and all the variables

-7n+8(-4n+1)-(5n-2(3n-4))=0

We multiply parentheses

-7n-32n-(5n-2(3n-4))+8=0



We calculate terms in parentheses: -(5n-2(3n-4)), so:

5n-2(3n-4)

We multiply parentheses

5n-6n+8

We add all the numbers together, and all the variables

-1n+8

Back to the equation:

-(-1n+8)



We add all the numbers together, and all the variables

-39n-(-1n+8)+8=0

We get rid of parentheses

-39n+1n-8+8=0

We add all the numbers together, and all the variables

-38n=0

n=0/-38

n=0

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