22-3c+4=2c+3+c

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Solution for 22-3c+4=2c+3+c equation: 



22-3c+4=2c+3+c

We move all terms to the left:

22-3c+4-(2c+3+c)=0

We add all the numbers together, and all the variables

-3c-(3c+3)+22+4=0

We add all the numbers together, and all the variables

-3c-(3c+3)+26=0

We get rid of parentheses

-3c-3c-3+26=0

We add all the numbers together, and all the variables

-6c+23=0

We move all terms containing c to the left, all other terms to the right

-6c=-23

c=-23/-6

c=3+5/6

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