22+(3-4x)-(1-x)=5x-2(x-3)

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Solution for 22+(3-4x)-(1-x)=5x-2(x-3) equation: 



22+(3-4x)-(1-x)=5x-2(x-3)

We move all terms to the left:

22+(3-4x)-(1-x)-(5x-2(x-3))=0

We add all the numbers together, and all the variables

(-4x+3)-(-1x+1)-(5x-2(x-3))+22=0

We get rid of parentheses

-4x+1x-(5x-2(x-3))+3-1+22=0



We calculate terms in parentheses: -(5x-2(x-3)), so:

5x-2(x-3)

We multiply parentheses

5x-2x+6

We add all the numbers together, and all the variables

3x+6

Back to the equation:

-(3x+6)



We add all the numbers together, and all the variables

-3x-(3x+6)+24=0

We get rid of parentheses

-3x-3x-6+24=0

We add all the numbers together, and all the variables

-6x+18=0

We move all terms containing x to the left, all other terms to the right

-6x=-18

x=-18/-6

x=+3

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