If it's not what You are looking for type in the equation solver your own equation and let us solve it.
6x(7+9x)=50
We move all terms to the left:
6x(7+9x)-(50)=0
We add all the numbers together, and all the variables
6x(9x+7)-50=0
We multiply parentheses
54x^2+42x-50=0
a = 54; b = 42; c = -50;
Δ = b2-4ac
Δ = 422-4·54·(-50)
Δ = 12564
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12564}=\sqrt{36*349}=\sqrt{36}*\sqrt{349}=6\sqrt{349}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-6\sqrt{349}}{2*54}=\frac{-42-6\sqrt{349}}{108} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+6\sqrt{349}}{2*54}=\frac{-42+6\sqrt{349}}{108} $
| 6x(7+9)=50 | | 0.25b=0.875 | | -5=t-10 | | 1/4x+10=1/4+54 | | -x+5x+17=1 | | 2(6x+8)=4(7x+9) | | -5+t=-16 | | 0.44=x+9/3x+6 | | 3/4u=-8 | | 1/9a=-9 | | 1/4b=7/8 | | 18x^2+39x-84=0 | | 2/3h+5=4-1/3h | | (f/9)+2=-1 | | c/7=63 | | 5×-4(4-x)=5×.8(x+24) | | 2(2x+4)=4+4(x+2) | | -3j=12 | | 2=(m/8)-1 | | 6=1/6z+8 | | 2m+10+m/2=5 | | 2(x+7)=9x-4 | | 4=8z-7+8z | | F(x)=x3-7x2+2x-40 | | 2-8m=-16-2m | | 2z-3+5z=18 | | 6+2m=-8 | | x/4=x/2 | | 8-3x+13=5x+21-8x | | (2x-3)+4x+(3x+1)=25 | | 2x^2-6x+5=4 | | 14=2c+9 |