22(3x+11)=10(7x+21)

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Solution for 22(3x+11)=10(7x+21) equation:



22(3x+11)=10(7x+21)
We move all terms to the left:
22(3x+11)-(10(7x+21))=0
We multiply parentheses
66x-(10(7x+21))+242=0
We calculate terms in parentheses: -(10(7x+21)), so:
10(7x+21)
We multiply parentheses
70x+210
Back to the equation:
-(70x+210)
We get rid of parentheses
66x-70x-210+242=0
We add all the numbers together, and all the variables
-4x+32=0
We move all terms containing x to the left, all other terms to the right
-4x=-32
x=-32/-4
x=+8

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