6(y-3)+10=2(3y-4)

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Solution for 6(y-3)+10=2(3y-4) equation: 



6(y-3)+10=2(3y-4)

We move all terms to the left:

6(y-3)+10-(2(3y-4))=0

We multiply parentheses

6y-(2(3y-4))-18+10=0



We calculate terms in parentheses: -(2(3y-4)), so:

2(3y-4)

We multiply parentheses

6y-8

Back to the equation:

-(6y-8)



We add all the numbers together, and all the variables

6y-(6y-8)-8=0

We get rid of parentheses

6y-6y+8-8=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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