21m2-41m+10=0

Solution for 21m2-41m+10=0 equation:

21m^2-41m+10=0

a = 21; b = -41; c = +10;
Δ = b2-4ac
Δ = -412-4·21·10
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-29}{2*21}=\frac{12}{42}
=2/7
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+29}{2*21}=\frac{70}{42}
=1+2/3
$