21=5/2(b1+b2)

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Solution for 21=5/2(b1+b2) equation:



21=5/2(b1+b2)
We move all terms to the left:
21-(5/2(b1+b2))=0
Domain of the equation: 2(b1+b2))!=0
b∈R
We add all the numbers together, and all the variables
-(5/2(+b+b^2))+21=0
We multiply all the terms by the denominator
-(5+21*2(+b+b^2))=0
We calculate terms in parentheses: -(5+21*2(+b+b^2)), so:
5+21*2(+b+b^2)
determiningTheFunctionDomain 21*2(+b+b^2)+5
Wy multiply elements
42b(++5
We use the square of the difference formula
42b(+5
Back to the equation:
-(42b(+5)
We add all the numbers together, and all the variables
-(42b5=0

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