210=2(c-50+60)-(c+60)

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Solution for 210=2(c-50+60)-(c+60) equation: 



210=2(c-50+60)-(c+60)

We move all terms to the left:

210-(2(c-50+60)-(c+60))=0

We add all the numbers together, and all the variables

-(2(c+10)-(c+60))+210=0



We calculate terms in parentheses: -(2(c+10)-(c+60)), so:

2(c+10)-(c+60)

We multiply parentheses

2c-(c+60)+20

We get rid of parentheses

2c-c-60+20

We add all the numbers together, and all the variables

c-40

Back to the equation:

-(c-40)



We get rid of parentheses

-c+40+210=0

We add all the numbers together, and all the variables

-1c+250=0

We move all terms containing c to the left, all other terms to the right

-c=-250

c=-250/-1

c=+250

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