20-(n-4)=4(n+5)

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Solution for 20-(n-4)=4(n+5) equation: 



20-(n-4)=4(n+5)

We move all terms to the left:

20-(n-4)-(4(n+5))=0

We get rid of parentheses

-n-(4(n+5))+4+20=0



We calculate terms in parentheses: -(4(n+5)), so:

4(n+5)

We multiply parentheses

4n+20

Back to the equation:

-(4n+20)



We add all the numbers together, and all the variables

-1n-(4n+20)+24=0

We get rid of parentheses

-1n-4n-20+24=0

We add all the numbers together, and all the variables

-5n+4=0

We move all terms containing n to the left, all other terms to the right

-5n=-4

n=-4/-5

n=4/5

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