3(2x-7)+28=6(x+1)

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Solution for 3(2x-7)+28=6(x+1) equation: 



3(2x-7)+28=6(x+1)

We move all terms to the left:

3(2x-7)+28-(6(x+1))=0

We multiply parentheses

6x-(6(x+1))-21+28=0



We calculate terms in parentheses: -(6(x+1)), so:

6(x+1)

We multiply parentheses

6x+6

Back to the equation:

-(6x+6)



We add all the numbers together, and all the variables

6x-(6x+6)+7=0

We get rid of parentheses

6x-6x-6+7=0

We add all the numbers together, and all the variables

1!=0

There is no solution for this equation

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