21/4+3(x+4)=4x+6(x+2)

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Solution for 21/4+3(x+4)=4x+6(x+2) equation: 



21/4+3(x+4)=4x+6(x+2)

We move all terms to the left:

21/4+3(x+4)-(4x+6(x+2))=0

We multiply parentheses

3x-(4x+6(x+2))+12+21/4=0

We multiply all the terms by the denominator


3x*4-((4x+6(x+2)))*4+21+12*4=0

We add all the numbers together, and all the variables

3x*4-((4x+6(x+2)))*4+69=0

Wy multiply elements

12x-((4x+6(x+2)))*4+69=0

We move all terms containing x to the left, all other terms to the right

12x-((4x+6(x+2)))*4=-69

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