10(2x+4)+3(x-3)=186-5(2x+8)

Solution for 10(2x+4)+3(x-3)=186-5(2x+8) equation:

10(2x+4)+3(x-3)=186-5(2x+8)

We move all terms to the left:

10(2x+4)+3(x-3)-(186-5(2x+8))=0

We multiply parentheses

20x+3x-(186-5(2x+8))+40-9=0


We calculate terms in parentheses: -(186-5(2x+8)), so:

186-5(2x+8)

determiningTheFunctionDomain
-5(2x+8)+186

We multiply parentheses

-10x-40+186

We add all the numbers together, and all the variables

-10x+146

Back to the equation:

-(-10x+146)


We add all the numbers together, and all the variables

23x-(-10x+146)+31=0

We get rid of parentheses

23x+10x-146+31=0

We add all the numbers together, and all the variables

33x-115=0

We move all terms containing x to the left, all other terms to the right

33x=115

x=115/33

x=3+16/33