7c(7c+1)-4c=13(3c-2)

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Solution for 7c(7c+1)-4c=13(3c-2) equation: 



7c(7c+1)-4c=13(3c-2)

We move all terms to the left:

7c(7c+1)-4c-(13(3c-2))=0

We add all the numbers together, and all the variables

-4c+7c(7c+1)-(13(3c-2))=0

We multiply parentheses

49c^2-4c+7c-(13(3c-2))=0



We calculate terms in parentheses: -(13(3c-2)), so:

13(3c-2)

We multiply parentheses

39c-26

Back to the equation:

-(39c-26)



We add all the numbers together, and all the variables

49c^2+3c-(39c-26)=0

We get rid of parentheses

49c^2+3c-39c+26=0

We add all the numbers together, and all the variables

49c^2-36c+26=0

a = 49; b = -36; c = +26;
Δ = b2-4ac
Δ = -362-4·49·26
Δ = -3800
Delta is less than zero, so there is no solution for the equation

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