20x2=-67x+56

Solution for 20x2=-67x+56 equation:

20x^2=-67x+56

We move all terms to the left:

20x^2-(-67x+56)=0

We get rid of parentheses

20x^2+67x-56=0

a = 20; b = 67; c = -56;
Δ = b2-4ac
Δ = 672-4·20·(-56)
Δ = 8969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(67)-\sqrt{8969}}{2*20}=\frac{-67-\sqrt{8969}}{40}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(67)+\sqrt{8969}}{2*20}=\frac{-67+\sqrt{8969}}{40}
$