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7(x-1)=3(x+4)+1
We move all terms to the left:
7(x-1)-(3(x+4)+1)=0
We multiply parentheses
7x-(3(x+4)+1)-7=0
We calculate terms in parentheses: -(3(x+4)+1), so:We get rid of parentheses
3(x+4)+1
We multiply parentheses
3x+12+1
We add all the numbers together, and all the variables
3x+13
Back to the equation:
-(3x+13)
7x-3x-13-7=0
We add all the numbers together, and all the variables
4x-20=0
We move all terms containing x to the left, all other terms to the right
4x=20
x=20/4
x=5
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