20x2-2x=120

Solution for 20x2-2x=120 equation:

20x^2-2x=120

We move all terms to the left:

20x^2-2x-(120)=0

a = 20; b = -2; c = -120;
Δ = b2-4ac
Δ = -22-4·20·(-120)
Δ = 9604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9604}=98$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-98}{2*20}=\frac{-96}{40}
=-2+2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+98}{2*20}=\frac{100}{40}
=2+1/2
$