3(2d-1)-2d=4(d2)+5

Solution for 3(2d-1)-2d=4(d2)+5 equation:

3(2d-1)-2d=4(d2)+5

We move all terms to the left:

3(2d-1)-2d-(4(d2)+5)=0

We add all the numbers together, and all the variables

-(+4d^2+5)+3(2d-1)-2d=0

We add all the numbers together, and all the variables

-(+4d^2+5)-2d+3(2d-1)=0

We multiply parentheses

-(+4d^2+5)-2d+6d-3=0

We get rid of parentheses

-4d^2-2d+6d-5-3=0

We add all the numbers together, and all the variables

-4d^2+4d-8=0

a = -4; b = 4; c = -8;
Δ = b2-4ac
Δ = 42-4·(-4)·(-8)
Δ = -112
Delta is less than zero, so there is no solution for the equation