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20x^2+80x=35+20x
We move all terms to the left:
20x^2+80x-(35+20x)=0
We add all the numbers together, and all the variables
20x^2+80x-(20x+35)=0
We get rid of parentheses
20x^2+80x-20x-35=0
We add all the numbers together, and all the variables
20x^2+60x-35=0
a = 20; b = 60; c = -35;
Δ = b2-4ac
Δ = 602-4·20·(-35)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6400}=80$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-80}{2*20}=\frac{-140}{40} =-3+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+80}{2*20}=\frac{20}{40} =1/2 $
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