20x2+5x=0

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Solution for 20x2+5x=0 equation:



20x^2+5x=0
a = 20; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·20·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*20}=\frac{-10}{40} =-1/4 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*20}=\frac{0}{40} =0 $

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