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20x-10-(5x(3x+1)-3x(6x-5))-5x(6x+1)=0
We multiply parentheses
-30x^2+20x-(5x(3x+1)-3x(6x-5))-5x-10=0
We calculate terms in parentheses: -(5x(3x+1)-3x(6x-5)), so:We add all the numbers together, and all the variables
5x(3x+1)-3x(6x-5)
We multiply parentheses
15x^2-18x^2+5x+15x
We add all the numbers together, and all the variables
-3x^2+20x
Back to the equation:
-(-3x^2+20x)
-30x^2-(-3x^2+20x)+15x-10=0
We get rid of parentheses
-30x^2+3x^2-20x+15x-10=0
We add all the numbers together, and all the variables
-27x^2-5x-10=0
a = -27; b = -5; c = -10;
Δ = b2-4ac
Δ = -52-4·(-27)·(-10)
Δ = -1055
Delta is less than zero, so there is no solution for the equation
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