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36/x=(20x+1)/9
We move all terms to the left:
36/x-((20x+1)/9)=0
Domain of the equation: x!=0We calculate fractions
x∈R
()/9x^2+(-((20x+1)*x)/9x^2=0
We multiply all the terms by the denominator
(-((20x+1)*x)+()=0
We calculate terms in parentheses: +(-((20x+1)*x)+(), so:We get rid of parentheses
-((20x+1)*x)+(
We add all the numbers together, and all the variables
-((20x+1)*x)
We calculate terms in parentheses: -((20x+1)*x), so:We get rid of parentheses
(20x+1)*x
We multiply parentheses
20x^2+x
Back to the equation:
-(20x^2+x)
-20x^2-x
We add all the numbers together, and all the variables
-20x^2-1x
Back to the equation:
+(-20x^2-1x)
-20x^2-1x=0
a = -20; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·(-20)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*-20}=\frac{0}{-40} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*-20}=\frac{2}{-40} =-1/20 $
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