20x+10(2x-3)5(3x-4)(3x+7)=1059

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Solution for 20x+10(2x-3)5(3x-4)(3x+7)=1059 equation: 



20x+10(2x-3)5(3x-4)(3x+7)=1059

We move all terms to the left:

20x+10(2x-3)5(3x-4)(3x+7)-(1059)=0

We multiply parentheses ..

10(2x-3)5(+9x^2+21x-12x-28)+20x-1059=0

We move all terms containing x to the left, all other terms to the right

10(2x-3)5(+9x^2+21x-12x-28)+20x=1059

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