20=4/5x+12

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Solution for 20=4/5x+12 equation: 



20=4/5x+12

We move all terms to the left:

20-(4/5x+12)=0



Domain of the equation: 5x+12)!=0

x∈R



We get rid of parentheses

-4/5x-12+20=0

We multiply all the terms by the denominator


-12*5x+20*5x-4=0

Wy multiply elements

-60x+100x-4=0

We add all the numbers together, and all the variables

40x-4=0

We move all terms containing x to the left, all other terms to the right

40x=4

x=4/40

x=1/10

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