(2x+15)=(7+12)+(3x+9)

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Solution for (2x+15)=(7+12)+(3x+9) equation: 



(2x+15)=(7+12)+(3x+9)

We move all terms to the left:

(2x+15)-((7+12)+(3x+9))=0

We add all the numbers together, and all the variables

(2x+15)-(19+(3x+9))=0

We get rid of parentheses

2x-(19+(3x+9))+15=0



We calculate terms in parentheses: -(19+(3x+9)), so:

19+(3x+9)

determiningTheFunctionDomain
(3x+9)+19

We get rid of parentheses

3x+9+19

We add all the numbers together, and all the variables

3x+28

Back to the equation:

-(3x+28)



We get rid of parentheses

2x-3x-28+15=0

We add all the numbers together, and all the variables

-1x-13=0

We move all terms containing x to the left, all other terms to the right

-x=13

x=13/-1

x=-13

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