20=4(c+3)

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Solution for 20=4(c+3) equation: 



20=4(c+3)

We move all terms to the left:

20-(4(c+3))=0



We calculate terms in parentheses: -(4(c+3)), so:

4(c+3)

We multiply parentheses

4c+12

Back to the equation:

-(4c+12)



We get rid of parentheses

-4c-12+20=0

We add all the numbers together, and all the variables

-4c+8=0

We move all terms containing c to the left, all other terms to the right

-4c=-8

c=-8/-4

c=+2

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