4(2r-3)-2(r-4)=3(r-3)

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Solution for 4(2r-3)-2(r-4)=3(r-3) equation: 



4(2r-3)-2(r-4)=3(r-3)

We move all terms to the left:

4(2r-3)-2(r-4)-(3(r-3))=0

We multiply parentheses

8r-2r-(3(r-3))-12+8=0



We calculate terms in parentheses: -(3(r-3)), so:

3(r-3)

We multiply parentheses

3r-9

Back to the equation:

-(3r-9)



We add all the numbers together, and all the variables

6r-(3r-9)-4=0

We get rid of parentheses

6r-3r+9-4=0

We add all the numbers together, and all the variables

3r+5=0

We move all terms containing r to the left, all other terms to the right

3r=-5

r=-5/3

r=-1+2/3

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