20=3-5(p-2)

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Solution for 20=3-5(p-2) equation: 



20=3-5(p-2)

We move all terms to the left:

20-(3-5(p-2))=0



We calculate terms in parentheses: -(3-5(p-2)), so:

3-5(p-2)

determiningTheFunctionDomain
-5(p-2)+3

We multiply parentheses

-5p+10+3

We add all the numbers together, and all the variables

-5p+13

Back to the equation:

-(-5p+13)



We get rid of parentheses

5p-13+20=0

We add all the numbers together, and all the variables

5p+7=0

We move all terms containing p to the left, all other terms to the right

5p=-7

p=-7/5

p=-1+2/5

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