-3(y+2)+39=5(3-y)

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Solution for -3(y+2)+39=5(3-y) equation: 



-3(y+2)+39=5(3-y)

We move all terms to the left:

-3(y+2)+39-(5(3-y))=0

We add all the numbers together, and all the variables

-3(y+2)-(5(-1y+3))+39=0

We multiply parentheses

-3y-(5(-1y+3))-6+39=0



We calculate terms in parentheses: -(5(-1y+3)), so:

5(-1y+3)

We multiply parentheses

-5y+15

Back to the equation:

-(-5y+15)



We add all the numbers together, and all the variables

-3y-(-5y+15)+33=0

We get rid of parentheses

-3y+5y-15+33=0

We add all the numbers together, and all the variables

2y+18=0

We move all terms containing y to the left, all other terms to the right

2y=-18

y=-18/2

y=-9

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