20=2(n-3)

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Solution for 20=2(n-3) equation: 



20=2(n-3)

We move all terms to the left:

20-(2(n-3))=0



We calculate terms in parentheses: -(2(n-3)), so:

2(n-3)

We multiply parentheses

2n-6

Back to the equation:

-(2n-6)



We get rid of parentheses

-2n+6+20=0

We add all the numbers together, and all the variables

-2n+26=0

We move all terms containing n to the left, all other terms to the right

-2n=-26

n=-26/-2

n=+13

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