x*10+(30*x)/10-(x-1)+2)=(1+1/x)

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Solution for x*10+(30*x)/10-(x-1)+2)=(1+1/x) equation:



x*10+(30x)/10-(x-1)+2)=(1+1/x)
We move all terms to the left:
x*10+(30x)/10-(x-1)+2)-((1+1/x))=0
Domain of the equation: x))!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
x*10+30x/10-(x-1)+2)-((1/x+1))=0
Wy multiply elements
10x+30x/10-(x-1)+2)-((1/x+1))=0
We get rid of parentheses
10x+30x/10-x+2)-((1/x+1))+1=0
We calculate fractions
30x^2/10x+10x-x+()/10x=0
We add all the numbers together, and all the variables
30x^2/10x+9x+()/10x=0
We multiply all the terms by the denominator
30x^2+9x*10x+()=0
We add all the numbers together, and all the variables
30x^2+9x*10x=0
Wy multiply elements
30x^2+90x^2=0
We add all the numbers together, and all the variables
120x^2=0
a = 120; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·120·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{240}=0$

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