20=-4(4x+1)+2(-5+3x)

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Solution for 20=-4(4x+1)+2(-5+3x) equation: 



20=-4(4x+1)+2(-5+3x)

We move all terms to the left:

20-(-4(4x+1)+2(-5+3x))=0

We add all the numbers together, and all the variables

-(-4(4x+1)+2(3x-5))+20=0



We calculate terms in parentheses: -(-4(4x+1)+2(3x-5)), so:

-4(4x+1)+2(3x-5)

We multiply parentheses

-16x+6x-4-10

We add all the numbers together, and all the variables

-10x-14

Back to the equation:

-(-10x-14)



We get rid of parentheses

10x+14+20=0

We add all the numbers together, and all the variables

10x+34=0

We move all terms containing x to the left, all other terms to the right

10x=-34

x=-34/10

x=-3+2/5

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