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0.3x-15=0/2x-5
We move all terms to the left:
0.3x-15-(0/2x-5)=0
Domain of the equation: 2x-5)!=0We get rid of parentheses
x∈R
0.3x-0/2x+5-15=0
We multiply all the terms by the denominator
(0.3x)*2x+5*2x-15*2x-0=0
We add all the numbers together, and all the variables
(+0.3x)*2x+5*2x-15*2x-0=0
We add all the numbers together, and all the variables
(+0.3x)*2x+5*2x-15*2x=0
We multiply parentheses
0x^2+5*2x-15*2x=0
Wy multiply elements
0x^2+10x-30x=0
We add all the numbers together, and all the variables
x^2-20x=0
a = 1; b = -20; c = 0;
Δ = b2-4ac
Δ = -202-4·1·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-20}{2*1}=\frac{0}{2} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+20}{2*1}=\frac{40}{2} =20 $
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