20=-2(24-y)+3(y-4)

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Solution for 20=-2(24-y)+3(y-4) equation: 



20=-2(24-y)+3(y-4)

We move all terms to the left:

20-(-2(24-y)+3(y-4))=0

We add all the numbers together, and all the variables

-(-2(-1y+24)+3(y-4))+20=0



We calculate terms in parentheses: -(-2(-1y+24)+3(y-4)), so:

-2(-1y+24)+3(y-4)

We multiply parentheses

2y+3y-48-12

We add all the numbers together, and all the variables

5y-60

Back to the equation:

-(5y-60)



We get rid of parentheses

-5y+60+20=0

We add all the numbers together, and all the variables

-5y+80=0

We move all terms containing y to the left, all other terms to the right

-5y=-80

y=-80/-5

y=+16

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