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5(3x-9)-4=5(x-3)+16
We move all terms to the left:
5(3x-9)-4-(5(x-3)+16)=0
We multiply parentheses
15x-(5(x-3)+16)-45-4=0
We calculate terms in parentheses: -(5(x-3)+16), so:We add all the numbers together, and all the variables
5(x-3)+16
We multiply parentheses
5x-15+16
We add all the numbers together, and all the variables
5x+1
Back to the equation:
-(5x+1)
15x-(5x+1)-49=0
We get rid of parentheses
15x-5x-1-49=0
We add all the numbers together, and all the variables
10x-50=0
We move all terms containing x to the left, all other terms to the right
10x=50
x=50/10
x=5
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