20=(1/2)(17+7x-5)

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Solution for 20=(1/2)(17+7x-5) equation: 



20=(1/2)(17+7x-5)

We move all terms to the left:

20-((1/2)(17+7x-5))=0



Domain of the equation: 2)(17+7x-5))!=0

x∈R



We add all the numbers together, and all the variables

-((+1/2)(7x+12))+20=0

We multiply parentheses ..

-((+7x^2+1/2*12))+20=0

We multiply all the terms by the denominator


-((+7x^2+1+20*2*12))=0



We calculate terms in parentheses: -((+7x^2+1+20*2*12)), so:

(+7x^2+1+20*2*12)

We get rid of parentheses

7x^2+1+20*2*12

We add all the numbers together, and all the variables

7x^2+481

Back to the equation:

-(7x^2+481)



We get rid of parentheses

-7x^2-481=0

a = -7; b = 0; c = -481;
Δ = b2-4ac
Δ = 02-4·(-7)·(-481)
Δ = -13468
Delta is less than zero, so there is no solution for the equation

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