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3/4w-1/w-4=12
We move all terms to the left:
3/4w-1/w-4-(12)=0
Domain of the equation: 4w!=0
w!=0/4
w!=0
w∈R
Domain of the equation: w!=0We add all the numbers together, and all the variables
w∈R
3/4w-1/w-16=0
We calculate fractions
3w/4w^2+(-4w)/4w^2-16=0
We multiply all the terms by the denominator
3w+(-4w)-16*4w^2=0
Wy multiply elements
-64w^2+3w+(-4w)=0
We get rid of parentheses
-64w^2+3w-4w=0
We add all the numbers together, and all the variables
-64w^2-1w=0
a = -64; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·(-64)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*-64}=\frac{0}{-128} =0 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*-64}=\frac{2}{-128} =-1/64 $
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