200=x+3x+3(x+3x)

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Solution for 200=x+3x+3(x+3x) equation: 



200=x+3x+3(x+3x)

We move all terms to the left:

200-(x+3x+3(x+3x))=0

We add all the numbers together, and all the variables

-(x+3x+3(+4x))+200=0



We calculate terms in parentheses: -(x+3x+3(+4x)), so:

x+3x+3(+4x)

We add all the numbers together, and all the variables

4x+3(+4x)

We multiply parentheses

4x+12x

We add all the numbers together, and all the variables

16x

Back to the equation:

-(16x)



We move all terms containing x to the left, all other terms to the right

-16x=-200

x=-200/-16

x=12+1/2

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