If it's not what You are looking for type in the equation solver your own equation and let us solve it.
200=x+3x+3x(x+3x)
We move all terms to the left:
200-(x+3x+3x(x+3x))=0
We add all the numbers together, and all the variables
-(x+3x+3x(+4x))+200=0
We calculate terms in parentheses: -(x+3x+3x(+4x)), so:We get rid of parentheses
x+3x+3x(+4x)
We add all the numbers together, and all the variables
4x+3x(+4x)
We multiply parentheses
12x^2+4x
Back to the equation:
-(12x^2+4x)
-12x^2-4x+200=0
a = -12; b = -4; c = +200;
Δ = b2-4ac
Δ = -42-4·(-12)·200
Δ = 9616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9616}=\sqrt{16*601}=\sqrt{16}*\sqrt{601}=4\sqrt{601}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4\sqrt{601}}{2*-12}=\frac{4-4\sqrt{601}}{-24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4\sqrt{601}}{2*-12}=\frac{4+4\sqrt{601}}{-24} $
| 5(t+3t)=4 | | (x-2)²=45 | | 5+4(t-3)=17 | | 10h-14=36 | | 5^x+5^x+5^2=650 | | 5^x+5^x+2=650 | | 3/4{m+12}=21 | | 11.40k+53.20=19 | | 3x3-x2+2x-4=0 | | 1.1{-0.3w+10}=7.7 | | 3X2+2x+4=0 | | 13x^2+8x=-8 | | 66+0.33x=68 | | 3x-12=60-x | | 24=90/x^2 | | 3=-16x^2+56x+6 | | (x-24)/x=0.83 | | 9(n-3)=72=3 | | 8=6/7t+5 | | 2(n-4)=12=2 | | 3x^2=3=0 | | 21+4u=41 | | X4+x2=30 | | 2=(v+7) | | -16x^2+56x+6=0 | | =7+9(-2n+9)+1 | | 0=3(2-(2x)/40) | | -7-4=3x+8-2x | | 2x-5+3x10=180 | | -2/3-y=24 | | =-6(-6a-3)-2+8a | | (x−9)(x−10)=−11x+83 |