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200=5x^2
We move all terms to the left:
200-(5x^2)=0
a = -5; b = 0; c = +200;
Δ = b2-4ac
Δ = 02-4·(-5)·200
Δ = 4000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4000}=\sqrt{400*10}=\sqrt{400}*\sqrt{10}=20\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{10}}{2*-5}=\frac{0-20\sqrt{10}}{-10} =-\frac{20\sqrt{10}}{-10} =-\frac{2\sqrt{10}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{10}}{2*-5}=\frac{0+20\sqrt{10}}{-10} =\frac{20\sqrt{10}}{-10} =\frac{2\sqrt{10}}{-1} $
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