n=(n-1)+3n+2

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Solution for n=(n-1)+3n+2 equation: 



n=(n-1)+3n+2

We move all terms to the left:

n-((n-1)+3n+2)=0



We calculate terms in parentheses: -((n-1)+3n+2), so:

(n-1)+3n+2

We add all the numbers together, and all the variables

3n+(n-1)+2

We get rid of parentheses

3n+n-1+2

We add all the numbers together, and all the variables

4n+1

Back to the equation:

-(4n+1)



We get rid of parentheses

n-4n-1=0

We add all the numbers together, and all the variables

-3n-1=0

We move all terms containing n to the left, all other terms to the right

-3n=1

n=1/-3

n=-1/3

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