20/5+2/5x=5x

Solution for 20/5+2/5x=5x equation:

20/5+2/5x=5x

We move all terms to the left:

20/5+2/5x-(5x)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R


We add all the numbers together, and all the variables

-5x+2/5x+4=0

We multiply all the terms by the denominator


-5x*5x+4*5x+2=0

Wy multiply elements

-25x^2+20x+2=0

a = -25; b = 20; c = +2;
Δ = b2-4ac
Δ = 202-4·(-25)·2
Δ = 600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{600}=\sqrt{100*6}=\sqrt{100}*\sqrt{6}=10\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-10\sqrt{6}}{2*-25}=\frac{-20-10\sqrt{6}}{-50}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+10\sqrt{6}}{2*-25}=\frac{-20+10\sqrt{6}}{-50}
$