15-(10x-3)=10x+4(-2x+1)

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Solution for 15-(10x-3)=10x+4(-2x+1) equation: 



15-(10x-3)=10x+4(-2x+1)

We move all terms to the left:

15-(10x-3)-(10x+4(-2x+1))=0

We get rid of parentheses

-10x-(10x+4(-2x+1))+3+15=0



We calculate terms in parentheses: -(10x+4(-2x+1)), so:

10x+4(-2x+1)

We multiply parentheses

10x-8x+4

We add all the numbers together, and all the variables

2x+4

Back to the equation:

-(2x+4)



We add all the numbers together, and all the variables

-10x-(2x+4)+18=0

We get rid of parentheses

-10x-2x-4+18=0

We add all the numbers together, and all the variables

-12x+14=0

We move all terms containing x to the left, all other terms to the right

-12x=-14

x=-14/-12

x=1+1/6

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