20/(2x-8)+1/(x-4)=11/2

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Solution for 20/(2x-8)+1/(x-4)=11/2 equation:


D( x )

2*x-8 = 0

x-4 = 0

2*x-8 = 0

2*x-8 = 0

2*x-8 = 0 // + 8

2*x = 8 // : 2

x = 8/2

x = 4

x-4 = 0

x-4 = 0

x-4 = 0 // + 4

x = 4

x in (-oo:4) U (4:+oo)

20/(2*x-8)+1/(x-4) = 11/2 // - 11/2

20/(2*x-8)+1/(x-4)-(11/2) = 0

20/(2*x-8)+1/(x-4)-11/2 = 0

(2*20*(x-4))/(2*(2*x-8)*(x-4))+(1*2*(2*x-8))/(2*(2*x-8)*(x-4))+(-11*(2*x-8)*(x-4))/(2*(2*x-8)*(x-4)) = 0

2*20*(x-4)+1*2*(2*x-8)-11*(2*x-8)*(x-4) = 0

44*x-22*x^2+176*x-352-176 = 0

220*x-22*x^2-528 = 0

220*x-22*x^2-528 = 0

22*(10*x-x^2-24) = 0

10*x-x^2-24 = 0

DELTA = 10^2-(-24*(-1)*4)

DELTA = 4

DELTA > 0

x = (4^(1/2)-10)/(-1*2) or x = (-4^(1/2)-10)/(-1*2)

x = 4 or x = 6

22*(x-4)*(x-6) = 0

(22*(x-4)*(x-6))/(2*(2*x-8)*(x-4)) = 0

(22*(x-4)*(x-6))/(2*(2*x-8)*(x-4)) = 0 // * 2*(2*x-8)*(x-4)

22*(x-4)*(x-6) = 0

( x-4 )

x-4 = 0 // + 4

x = 4

( x-6 )

x-6 = 0 // + 6

x = 6

x in { 4}

x = 6

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